ăăŒă«ăăŹăăéŁæéèšçźæ©ăźäœżăæč
ăăŒă«ăăŹăăïŒäœăçœźăïŒăŻ1ćăźèȘżçă§è€æ°éŁćăăŸăšăăŠäœăăăăăŻăăăłă°ăźæčæłă§ăăăăźèšçźæ©ăŻăŹă·ăăźćșæșäșșæ°ăšćźéă«éŁăčăäșșæ°ă»ćæ°ăć „ćăăă ăă§ăćż èŠăȘéŁæăźćçăèȘćçă«èšçźăăŸăă
ć „ćé çźăźèȘŹæ
ăŹă·ăăźćșæșäșșæ°ïŒäœżçšăăăŹă·ăă«èšèŒăăăŠăăăăäșșćăăźæ°ćăć „ćăăŸăăă2äșșćăăȘă2ăă4äșșćăăȘă4ă§ăă
ćźéă«éŁăčăäșșæ°ïŒăăŒă«ăăŹăăăăæçăéŁăčăćźéăźäșșæ°ă§ăă1äșșæźăăăȘă1ăć „ćăăŠăă ăăă
é±éăźéŁäșćæ°ïŒăăźæçă1é±éă§äœćéŁăčăăăć „ćăăŸăăćčłæ„5æ„ăźæŒéŁăȘă5ćăæŻæăȘă7ćă§ăă
èšçźćŒ
ćż èŠç·äșșć = ćźéăźäșșæ° Ă é±ééŁäșćæ°ăćç = ç·äșșć Ă· ăŹă·ăćșæșäșșæ°ă§ăăäŸăă°4äșșćăŹă·ăă2äșșă§é±6ćéŁăčăăȘă (2 Ă 6) Ă· 4 = 3ćăćż èŠă§ăă
ăăăăèłȘć
ć·è”äżćăȘă3ă5æ„ćăé©ćœă§ăăăă仄äžăźć ŽćăŻć·ćäżćăăéŁăčăćæ„ă«ć·è”ćș«ă§è§ŁćăăæčæłăăăăăăăŸăă
æăç©ăçéèăźă”ă©ăăŻæéăç”ă€ăšéŁæăæȘăăȘăăăäžćăă§ăăăčăŒăă»ç źç©ă»ă°ăȘă«æçă»èčă§ç©ç©ăȘă©ăäżćă«é©ăăŠăăŸăă
äŸăă°1.5ćăćż èŠăȘăăéŁæăăăčăŠ1.5ćă§æșćăăŠăă ăăăć”ăźăăă«ććČăă«ăăăăźăŻćăäžăăŠçšæăăäœăŁăćăŻć„ăźæçă«æŽ»çšăăŸăăăă